题目
A.f(a)>eaf(0) | B.f(a)<eaf(0) | C.f(a)<
|
D.f(a)>
|
答案
∵f"(x)+f(x)>0
∴F′(x)=(ex)′×f(x)+ex×f′(x)
=ex×f(x)+ex×f′(x)
=ex(f"(x)+f(x))>0,
∴F(x)=ex×f(x)为增函数,又a>0,
∴F(a)>F(0),即eaf(a)>e0f(0)=f(0),
∴f(a)>
f(0) |
ea |
故选D.
A.f(a)>eaf(0) | B.f(a)<eaf(0) | C.f(a)<
|
D.f(a)>
|
f(0) |
ea |