题目
(2)已知x∈R,求函数y=3(4x+4-x)-10(2x+2-x)的最小值.
(3)已知2x≤256且log2x≥
| 1 |
| 2 |
| x |
| 2 |
答案 | |
| (1)lg|x|+lg|7-x|=lg|7x-x2|.∵-1≤x≤2∴7x-x2∈[-8,10],|7x-x2|∈[0,10]∴最大值为1(此时x=2) (2)令t=(2x+2-x)(t≥2),则y=3t2-10t-6(t≥2),∴y≥-14(此时x=1) (3)由已知,
|
| 1 |
| 2 |
| x |
| 2 |
答案 | |
| (1)lg|x|+lg|7-x|=lg|7x-x2|.∵-1≤x≤2∴7x-x2∈[-8,10],|7x-x2|∈[0,10]∴最大值为1(此时x=2) (2)令t=(2x+2-x)(t≥2),则y=3t2-10t-6(t≥2),∴y≥-14(此时x=1) (3)由已知,
|