题目
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A.a>b>c | B.a>c>b | C.c>a>b | D.b>a>c |
答案
∴f(x+2)=f(-x+2),
∴f(x+4)=f(-x-2+2)=f(-x)=f(x).
∵a=f(log 27
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b=f(8.5)=f(8+0.5)=f(0.5)
c=f(-5)=f(-4-1)=f(-1)=f(1)
当x∈[0,2]时,f(x)是减函数
f(
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即a>b>c.
故选A.
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A.a>b>c | B.a>c>b | C.c>a>b | D.b>a>c |
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