题目
| x+1 |
| 4-2x |
| 1 |
| 2012 |
| 2 |
| 2012 |
| 2011 |
| 2012 |
答案
| x+1 |
| 4-2x |
| (1-x)+1 |
| 4-2(1-x) |
| x+1 |
| 4-2x |
| 2-x |
| 2+2x |
| 1 |
| 4 |
所以f(
| 1 |
| 2012 |
| 2 |
| 2012 |
| 2011 |
| 2012 |
=[f(
| 1 |
| 2012 |
| 2011 |
| 2012 |
| 2 |
| 2012 |
| 2010 |
| 2012 |
| 1005 |
| 2012 |
| 1007 |
| 2012 |
| 1006 |
| 2012 |
=(
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
故答案为:(
| 1 |
| 2 |
| x+1 |
| 4-2x |
| 1 |
| 2012 |
| 2 |
| 2012 |
| 2011 |
| 2012 |
| x+1 |
| 4-2x |
| (1-x)+1 |
| 4-2(1-x) |
| x+1 |
| 4-2x |
| 2-x |
| 2+2x |
| 1 |
| 4 |
| 1 |
| 2012 |
| 2 |
| 2012 |
| 2011 |
| 2012 |
| 1 |
| 2012 |
| 2011 |
| 2012 |
| 2 |
| 2012 |
| 2010 |
| 2012 |
| 1005 |
| 2012 |
| 1007 |
| 2012 |
| 1006 |
| 2012 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |