题目
| 5 |
| 4 |
| C | xn |
| n(n-1)(n-2)…(n-[x]+1) |
| x(x-1)…(x-[x]+1) |
| C |
|
| C | x8 |
答案
| 3 |
| 2 |
| 3 |
| 2 |
| C |
|
| 8 | ||
|
| 16 |
| 3 |
当x∈[2,3)时,∵[x]=2,∴Cxn=
| n(n-1) |
| x(x-1) |
∴Cx8=
| 8×7 |
| x(x-1) |
| 56 |
| x(x-1) |
又∵当x∈[2,3)时,f(x)=x(x-1)∈[2,6),
∴当[2,3)时,
| C | 28 |
| 8×7 |
| 2×1 |
当x→3时,[x]=2,
| C | x8 |
| 8×7 |
| 3×2 |
| 28 |
| 3 |
∴Cx8=
| 56 |
| x(x-1) |
| 28 |
| 3 |
故答案为:
| 16 |
| 3 |
| 28 |
| 3 |